Instructor: Yao Zhenwei
中文版:液晶
Back to: Soft Matter Physics Course Notes

Core Picture

Liquid crystals sit between liquids and crystals. A nematic phase has orientational order but no positional order. The director n represents average orientation, with n equivalent to -n.

Scalar and Tensor Order Parameters

Orientation can be described by f(theta, phi). With cylindrical symmetry around the director, it depends only on theta.

scalar S=S=⟨12(3cos⁡2θ−1)⟩S=\left\langle\frac12(3\cos^2\theta-1)\right\rangle
Legendre=S=⟨P2(cos⁡θ)⟩S=\langle P_2(\cos\theta)\rangle
tensor=Qαβ=S(nαnβ−δαβ/3)Q_{\alpha\beta}=S(n_\alpha n_\beta-\delta_{\alpha\beta}/3)
trace=Tr Q=0\mathrm{Tr}\,Q=0

S=1 means perfect alignment. S=0 means isotropic orientation. The Q tensor removes the isotropic part and keeps anisotropy.

Macroscopic Response Tensor

Nematic anisotropy can be measured through response to an external field.

response=Mα=χαβHβM_\alpha=\chi_{\alpha\beta}H_\beta
isotropic=χαβ=χ0δαβ\chi_{\alpha\beta}=\chi_0\delta_{\alpha\beta}
nematic=χαβ=χ⊥δαβ+χanαnβ\chi_{\alpha\beta}=\chi_\perp\delta_{\alpha\beta}+\chi_a n_\alpha n_\beta
anisotropy=χa=χ∥−χ⊥\chi_a=\chi_\parallel-\chi_\perp

Frank Free Energy

Spatial variation of director costs elastic energy. The three basic deformations are splay, twist, and bend.

Frank=F=12∫[K1(∇⋅n)2+K2(n⋅∇×n)2+K3∣n×∇×n∣2]dVF=\frac12\int[K_1(\nabla\cdot\mathbf n)^2+K_2(\mathbf n\cdot\nabla\times\mathbf n)^2+K_3|\mathbf n\times\nabla\times\mathbf n|^2]dV
splay=∇⋅n\nabla\cdot\mathbf n
twist=n⋅∇×n\mathbf n\cdot\nabla\times\mathbf n
bend=n×∇×n\mathbf n\times\nabla\times\mathbf n

In two dimensions and the one-constant approximation, the director is represented by an angle field theta.

2D n=n=(cos⁡θ,sin⁡θ)\mathbf n=(\cos\theta,\sin\theta)
one K=F=K2∫∣∇θ∣2d2rF=\frac{K}{2}\int|\nabla\theta|^2d^2r

Topological Defects

The total rotation of director around a defect defines its topological charge. Because n is equivalent to -n, half-integer defects are allowed.

charge=q=12π∮dθq=\frac{1}{2\pi}\oint d\theta
defect=θ=qφ+θ0\theta=q\varphi+\theta_0
energy=Fdefect≈πKq2ln⁡(R/a)F_{defect}\approx\pi Kq^2\ln(R/a)
sphere=∑iqi=2\sum_i q_i=2

A nematic on a sphere must carry total topological charge 2, often realized by four +1/2 defects.

Exam Cue

For liquid crystals, first state n is equivalent to -n, then write S or Q. If director varies, use Frank free energy. If defects appear, compute winding number and remember the spherical charge constraint.